SXMgdGhpcyBiYXNlPw==
解码后：Is this base?
base 隐写
Q2V0dGUgbnVpdCwK
SW50ZW5hYmxlIGluc29tbmllLAp=
TGEgZm9saWUgbWUgZ3VldHRlLAo=
SmUgc3VpcyBjZSBxdWUgamUgZnVpcwp=
SmUgc3ViaXMsCt==
Q2V0dGUgY2Fjb3Bob25pZSwK
UXVpIG1lIHNjaWUgbGEgdOmUmnRlLAp=
QXNzb21tYW50ZSBoYXJtb25pZSwK
RWxsZSBtZSBkaXQsCo==
VHUgcGFpZXJhcyB0ZXMgZGVsaXRzLAp=
UXVvaSBxdSdpbCBhZHZpZW5uZSwK
T24gdHJh5Y2vbmUgc2VzIGNoYeWNr25lcywK
U2VzIHBlaW5lcywK
SmUgdm91ZSBtZXMgbnVpdHMsCm==
QSBsJ2Fzc2FzeW1waG9uaWUsCl==
QXV4IHJlcXVpZW1zLAr=
VHVhbnQgcGFyIGRlcGl0LAq=
Q2UgcXVlIGplIHNlbWUsCt==
SmUgdm91ZSBtZXMgbnVpdHMsCp==
QSBsJ2Fzc2FzeW1waG9uaWUsCp==
RXQgYXV4IGJsYXNwaGVtZXMsCo==
Sidhdm91ZSBqZSBtYXVkaXMsCl==
VG91cyBjZXV4IHF1aSBzJ2FpbWVudCwK
TCdlbm5lbWksCu==
VGFwaSBkYW5zIG1vbiBlc3ByaXQsCp==
RumUmnRlIG1lcyBkZWZhaXRlcywK
U2FucyByZXBpdCBtZSBkZWZpZSwK
SmUgcmVuaWUsCq==
TGEgZmF0YWxlIGhlcmVzaWUsCh==
UXVpIHJvbmdlIG1vbiDplJp0cmUsCo==
SmUgdmV1eCByZW5h5Y2vdHJlLAp=
UmVuYeWNr3RyZSwK
SmUgdm91ZSBtZXMgbnVpdHMsCn==
QSBsJ2Fzc2FzeW1waG9uaWUsCq==
QXV4IHJlcXVpZW1zLAp=
VHVhbnQgcGFyIGRlcGl0LAq=
Q2UgcXVlIGplIHNlbWUsCo==
SmUgdm91ZSBtZXMgbnVpdHMsCm==
QSBsJ2Fzc2FzeW1waG9uaWUsCl==
RXQgYXV4IGJsYXNwaGVtZXMsCm==
Sidhdm91ZSBqZSBtYXVkaXMsCu==
VG91cyBjZXV4IHF1aSBzJ2FpbWVudCwK
UGxldXJlbnQgbGVzIHZpb2xvbnMgZGUgbWEgdmllLAp=
TGEgdmlvbGVuY2UgZGUgbWVzIGVudmllcywK
U2lwaG9ubmVlIHN5bXBob25pZSwK
RGVjb25jZXJ0YW50IGNvbmNlcnRvLAq=
SmUgam91ZSBzYW5zIHRvdWNoZXIgbGUgRG8sCo==
TW9uIHRhbGVudCBzb25uZSBmYXV4LAp=
SmUgbm9pZSBtb24gZW5udWksCo==
RGFucyBsYSBtZWxvbWFuaWUsCl==
SmUgdHVlIG1lcyBwaG9iaWVzLAq=
RGFucyBsYSBkZXNoYXJtb25pZSwK
SmUgdm91ZSBtZXMgbnVpdHMsCv==
QSBsJ2Fzc2FzeW1waG9uaWUsCn==
QXV4IHJlcXVpZW1zLAp=
VHVhbnQgcGFyIGRlcGl0LAo=
Q2UgcXVlIGplIHNlbWUsCm==
SmUgdm91ZSBtZXMgbnVpdHMsCp==
QSBsJ2Fzc2FzeW1waG9uaWUsCm==
RXQgYXV4IGJsYXNwaGVtZXMsCu==
Sidhdm91ZSBqZSBtYXVkaXMsCm==
VG91cyBjZXV4IHF1aSBzJ2FpbWVudCwK
SmUgdm91ZSBtZXMgbnVpdHMsCn==
QSBsJ2Fzc2FzeW1waG9uaWUgKGwnYXNzYXN5bXBob25pZSksCn==
Sidhdm91ZSBqZSBtYXVkaXMsCt==
VG91cyBjZXV4IHF1aSBzJ2FpbWVudA==
解释：
base64 加密流程：
abc: 01100001 01100010 01100011
011000 010110 001001 100011
换成十进制对应 "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/" 的数据。变成密文：TWFu
若不足三的倍数，若是两个就是加一个 =，一个就是两个 == 填充，在解密时这个是没用的
例如：01001101 就变成了 010011 010000 变成 TQ== , 这后面 4 个字节我就可以用来隐写，因为解密时是不会影响的，会被丢弃，所以 base64 就可以用来隐写
base64 隐写脚本：
import base64 | |
def get_base64_diff_value(s1, s2): | |
base64chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/' | |
res = 0 | |
for i in range(len(s2)): | |
if s1[i] != s2[i]: | |
return abs(base64chars.index(s1[i]) - base64chars.index(s2[i])) | |
return res | |
def solve_stego(): | |
with open('flag.txt', 'rb') as f: | |
file_lines = f.readlines() | |
bin_str = '' | |
for line in file_lines: | |
steg_line = line.strip().decode() | |
norm_line = base64.b64encode(base64.b64decode(line.strip())).decode() | |
diff = get_base64_diff_value(steg_line, norm_line) | |
print(diff) | |
pads_num = steg_line.count('=') | |
if diff: | |
bin_str += bin(diff)[2:].zfill(pads_num * 2) | |
else: | |
bin_str += '0' * pads_num * 2 | |
print(goflag(bin_str)) | |
def goflag(bin_str): | |
res_str = '' | |
for i in range(0, len(bin_str), 8): | |
res_str += chr(int(bin_str[i:i + 8], 2)) | |
return res_str | |
if __name__ == '__main__': | |
solve_stego() |
